A body of mass 5 kg explodes at rest into three fragments with masses in the ratio 1 : 1 : 3. The fragments with equal masses fly in mutually perpendicular directions with speeds of 21 m/s. The velocity of the heaviest fragment will be
Text Solution
Verified by ExpertsThe correct answer is:
D
∴ ∴ Resultant = 
kg m/s
The momentum of heavier fragment should be numerically equal to resultant of 
and 
.
∴ ∴ 
= 9.89 m/s
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